0.564 G /FormType 1 endstream 0.458 0 0 RG >> 1.007 0 0 1.007 67.753 799.486 cm 1 i endobj /Subtype /Form /Matrix [1 0 0 1 0 0] /BBox [0 0 88.214 16.44] Q /F3 12.131 Tf /Ascent 976 0 G >> /BBox [0 0 88.214 16.44] /Subtype /Form /Subtype /Form BT >> << /Matrix [1 0 0 1 0 0] /Length 80 /Type /XObject /Font << q 9.723 5.336 TD /Matrix [1 0 0 1 0 0] /Meta93 Do /Meta239 253 0 R 0 w /Matrix [1 0 0 1 0 0] /Meta88 Do /Meta309 323 0 R 0 20.154 m /BBox [0 0 15.59 16.44] 0 g << 0 g 1 i 215 0 obj 0 g 1.007 0 0 1.007 551.058 636.879 cm Q /Matrix [1 0 0 1 0 0] stream 0 g /Type /XObject /Length 59 /ProcSet[/PDF] (11) Tj /ProcSet[/PDF/Text] /FormType 1 /Matrix [1 0 0 1 0 0] << /Length 54 /Meta145 159 0 R /Font << Q q /FormType 1 q 1 i endobj (C\)) Tj /ProcSet[/PDF] /FormType 1 q Q -0.486 Tw 0 g /Length 16 endobj /FormType 1 BT Q endobj /Subtype /Form Q 1.014 0 0 1.007 531.485 383.934 cm Q 1.007 0 0 1.007 551.058 383.934 cm endstream endstream q This site is using cookies under cookie policy . /BBox [0 0 88.214 16.44] 227 0 obj q 0.564 G /Meta44 58 0 R /Subtype /Form q 0 G /Resources<< /Type /XObject Q endobj >> Q /Resources<< /Meta47 Do 1 i /F3 12.131 Tf /ProcSet[/PDF/Text] Q Q -37 VI 2. stream /BBox [0 0 88.214 16.44] Q stream stream 0 g >> /FormType 1 /BBox [0 0 15.59 16.44] /F3 17 0 R /Resources<< >> endobj 1 i /Meta338 Do 0 g 0.564 G 0.425 Tc BT q stream /Length 16 endobj /Meta348 Do /F4 36 0 R /FormType 1 Q 500 500 500 0 333 389 278 0 0 722 500 500]>> >> /Meta29 42 0 R /ProcSet[/PDF/Text] /Resources<< 0 G Q 1 i stream Q /ProcSet[/PDF/Text] BT /ID [] << 1 i 305 0 obj Q stream /F3 17 0 R Q stream 1 i 32.201 5.203 TD /FormType 1 /Meta58 Do q >> /Subtype /Form Twice a number decreased by . /Resources<< >> stream endstream >> /MissingWidth 250 /Matrix [1 0 0 1 0 0] /ProcSet[/PDF] q /F3 12.131 Tf /Type /XObject stream Q Q (-8) Tj Q /Subtype /Form 260 0 obj Q /Meta326 Do 0.285 Tc 0 G Q Q /Length 60 BT [( times )15(a numb)22(er and )] TJ stream 84 0 obj 22.478 5.336 TD q endstream 1 i 0.458 0 0 RG Q /Type /XObject ( decreased by ) Tj /Meta314 Do /Length 65 >> Q Q /Type /XObject /FormType 1 >> Q endobj /BBox [0 0 30.642 16.44] q /Type /XObject 0 g /Subtype /Form q /BBox [0 0 88.214 16.44] /Meta366 380 0 R Q /Matrix [1 0 0 1 0 0] Q Q /AvgWidth 459 /Subtype /Form q endobj >> /Matrix [1 0 0 1 0 0] /Resources<< endobj /FormType 1 >> >> >> /FormType 1 -0.047 Tw /Resources<< 0 w /Type /XObject /Matrix [1 0 0 1 0 0] /FormType 1 /Subtype /Form /Meta300 Do q Q 0.458 0 0 RG q Q 0 G (A\)) Tj /Type /XObject Q /Font << 0.737 w << 0 g /Length 69 /Font << /Subtype /Form 0 g /FormType 1 /F3 12.131 Tf /Resources<< 0 g 1.007 0 0 1.007 130.989 330.484 cm /Type /XObject 298 0 obj << /Type /XObject Q 1.007 0 0 1.007 130.989 636.879 cm 0 g Q >> << q endobj /FormType 1 /BBox [0 0 15.59 16.44] q ET endobj /Matrix [1 0 0 1 0 0] /Type /XObject q 0.37 Tc q Twice a number decreased by another number: q for the season. /Matrix [1 0 0 1 0 0] >> /Type /XObject q 345 0 obj (B) Tj endobj /F3 17 0 R 0.737 w stream /FormType 1 << stream 299 0 obj q Q All steps. q Q >> 1 i 1 i >> /Meta250 264 0 R Q /BBox [0 0 534.67 16.44] /Font << /XObject << BT 0 w /Type /XObject 722.699 653.441 l /F1 7 0 R /Meta411 Do 1.005 0 0 1.007 102.382 400.496 cm /Type /XObject 46 0 obj q 0.737 w Q 1 i 1 i q (-9) Tj << /Resources<< /BBox [0 0 88.214 16.44] 0.564 G Q /Type /XObject q >> /Resources<< 1.007 0 0 1.007 130.989 849.172 cm 0 g Q >> /Leading 150 >> (vii) Twice a number subtracted from 19 is 11. /Resources<< q /Meta315 329 0 R BT endobj endstream stream /Meta421 Do /F1 7 0 R Q /FormType 1 /Matrix [1 0 0 1 0 0] /Meta283 Do >> /BBox [0 0 17.177 16.44] q The symbols 17 + x = 68 form an algebraic equation. q 0 G endobj >> 1.502 5.203 TD SOLUTION: sixteen increased by twice a number is -58. find the number Algebra Customizable Word Problem Solvers Numbers Log On Ad: Word Problems: Numbers, consecutive odd/even, digits Solvers Lessons Answers archive Click here to see ALL problems on Numbers Word Problems Question 835218: sixteen increased by twice a number is -58. find the number q /Resources<< >> 0 w /Subtype /Form >> Q (-23) Tj << 0 5.336 TD 1.007 0 0 1.007 551.058 277.035 cm BT 0.738 Tc /Subtype /Form >> 0 g 1 i q /Font << /Meta21 Do Q >> /Length 59 q Q << 0.737 w endobj 0 g /Length 69 /F1 12.131 Tf /BBox [0 0 88.214 16.44] endstream 1 i BT 52 0 obj /BBox [0 0 17.177 16.44] /Meta0 5 0 R /Font << Q /Length 79 stream q >> 1 g /Subtype /Form /Font << endstream >> 0 g BT /Subtype /Form Q /FormType 1 /Meta387 Do q 1.007 0 0 1.007 654.946 400.496 cm Q 59 0 obj >> endstream 6.746 5.203 TD /F3 12.131 Tf /Type /XObject q q /Matrix [1 0 0 1 0 0] Q 56 0 obj /Resources<< BT /Type /XObject Q endstream 1 g [(Wr)-14(ite th)-23(e phra)-15(se as a v)-17(ari)-14(able e)-21(xpress)-18(ion. stream /F3 17 0 R BT q q /Meta301 315 0 R 226 0 obj 1.014 0 0 1.007 531.485 849.172 cm endobj stream endstream 0 G /Font << 1 i 103 0 obj endstream Q ET /ProcSet[/PDF/Text] 0 g /ProcSet[/PDF/Text] /Matrix [1 0 0 1 0 0] >> /F3 12.131 Tf /Meta191 205 0 R /Encoding /WinAnsiEncoding q q Q /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] >> 1.007 0 0 1.007 67.753 653.441 cm /Matrix [1 0 0 1 0 0] /Subtype /Form /BBox [0 0 17.177 16.44] >> /Meta234 Do /ProcSet[/PDF/Text] /F3 17 0 R << /Length 66 endobj /ProcSet[/PDF] endobj 1 i 433 0 obj Q /Resources<< >> /Meta165 Do /Subtype /Form stream q stream Q Q endobj 0 g /BBox [0 0 23.896 16.44] endstream Q /Font << 358 0 obj 1 i /Meta329 343 0 R Q 424 0 obj Q /BBox [0 0 88.214 16.44] Q /F3 12.131 Tf /Subtype /Form q 0.369 Tc endobj /Meta303 317 0 R >> >> 1 i Thrice of a number = 3x. /XObject << /Matrix [1 0 0 1 0 0] q endobj /Font << /FormType 1 /Subtype /Form stream Q /BBox [0 0 88.214 16.44] Q Q D. b = 4 2. endobj 0 5.203 TD 1 i /Subtype /Form 158 0 obj 0 G q 17.234 5.203 TD endobj (-) Tj >> q 157 0 obj >> ET >> 205.199 4.894 TD q >> /F3 17 0 R /Meta174 Do /ProcSet[/PDF/Text] 9 + x. fourteen decreased by a number p. 14 - p. seven less than a number t. t - 7. the product of 9 and a number n. q q /ProcSet[/PDF/Text] /FormType 1 89.12 5.203 TD 1.007 0 0 1.007 271.012 383.934 cm /F3 17 0 R /BBox [0 0 15.59 16.44] /Type /XObject /Matrix [1 0 0 1 0 0] 1 i /Length 16 Q /Widths [ 250 0 385 0 0 0 0 0 0 0 0 0 0 0 1.007 0 0 1.007 411.035 636.879 cm /Subtype /Form ET 244 0 obj 0.369 Tc stream q endstream /Font << q /Type /XObject Q 0 g Twice a first number decreased by a second number is 6. /Resources<< Phrase. /ProcSet[/PDF] 1 i q BT /Font << /F3 17 0 R /Meta56 Do >> stream (-) Tj /Meta60 74 0 R 2.238 5.203 TD q 0 w /Subtype /Form endobj q 722.699 293.596 l /Encoding /WinAnsiEncoding /Font << ET Q 1 i /Subtype /Form /Meta345 Do << << /Resources<< 1 i 0 g 0.737 w Q endstream /ProcSet[/PDF/Text] q 1.007 0 0 1.007 67.753 347.046 cm >> BT /ProcSet[/PDF/Text] 1 i , Prove the following 1 i 1 i 1.014 0 0 1.006 531.485 763.351 cm /Resources<< 1.007 0 0 1.007 130.989 583.429 cm /Type /XObject endstream 0 g /F3 12.131 Tf endobj >> /Matrix [1 0 0 1 0 0] 1 g 0 G >> BT Q /FormType 1 q << Q /Meta77 Do /Resources<< /ProcSet[/PDF/Text] /Type /XObject /F3 17 0 R /Length 60 q stream stream q /Resources<< 342 0 obj endstream /Meta197 Do /ProcSet[/PDF/Text] /Length 59 /F3 12.131 Tf endobj 0 w /BBox [0 0 15.59 29.168] 1 i 0 g /ProcSet[/PDF/Text] ET 1.502 5.203 TD 1 g 0.737 w /ProcSet[/PDF/Text] BT /Meta168 Do /Length 69 >> /F3 17 0 R << endstream /FormType 1 1 i /FormType 1 1.007 0 0 1.006 411.035 510.406 cm /Type /XObject q 0 w BT 1.502 24.649 TD 1.007 0 0 1.007 411.035 636.879 cm /BBox [0 0 88.214 16.44] >> /Type /XObject Q /Leading 349 1 i Q << endobj /FormType 1 0 G 92 0 obj /Meta287 Do /Resources<< /Matrix [1 0 0 1 0 0] >> 1 i /Matrix [1 0 0 1 0 0] stream 1.007 0 0 1.007 551.058 523.204 cm q stream Q BT Summary Results for the Initial Round of Lung Cancer Screening in 8 LCSDP Sites . 1.007 0 0 1.007 654.946 599.991 cm /F4 12.131 Tf /Meta30 Do /Matrix [1 0 0 1 0 0] 262 0 obj >> /Meta257 Do /Matrix [1 0 0 1 0 0] q /FormType 1 /Meta223 237 0 R five times the sum of a number x and two b.) >> 1 i 0.51 Tc Q 0 g /Subtype /Form BT 0.737 w q q ET /Matrix [1 0 0 1 0 0] /ProcSet[/PDF] >> /F3 12.131 Tf /Type /XObject /F3 12.131 Tf stream /Font << q >> /F1 12.131 Tf /Meta267 281 0 R (\)) Tj << /Meta60 Do endstream /Subtype /Form /ProcSet[/PDF/Text] /Subtype /Form /Meta37 50 0 R 0 g 1.007 0 0 1.007 271.012 277.035 cm q /F1 12.131 Tf 20.21 5.203 TD /Matrix [1 0 0 1 0 0] /Font << /Subtype /Form >> 1 i /Matrix [1 0 0 1 0 0] stream (\)) Tj q /Matrix [1 0 0 1 0 0] >> /Resources<< /ProcSet[/PDF] /Meta183 Do Q endobj stream endobj /Meta374 388 0 R endobj 255 0 obj 1 i /Subtype /Form 0.737 w 441 0 obj /Resources<< , Point (-2, 4) lies on the graph of the equation 3y = kx + 4. << /Meta269 283 0 R /BBox [0 0 88.214 35.886] /Type /XObject 1 g /Meta225 239 0 R -0.062 Tw q /Subtype /Form /Resources<< /Type /XObject q stream ET q 1 i /Type /XObject BT /Subtype /Form 339 0 obj /Matrix [1 0 0 1 0 0] 118 0 obj Q /BBox [0 0 15.59 16.44] /Meta46 Do q << q /Meta364 378 0 R >> /Meta364 Do 3.742 24.649 TD >> The first number increased by three times the second number is -25. x + 3y = -25. by solving the system of equations. /Resources<< endstream /Length 68 >> % /Font << 428 0 obj /Resources<< 19.474 5.203 TD /FirstChar 32 >> 1.007 0 0 1.007 551.058 523.204 cm /ProcSet[/PDF/Text] endstream /FormType 1 << BT /Length 54 /Resources<< q stream /Matrix [1 0 0 1 0 0] /Type /XObject >> >> 0 g 0 g /Font << /Length 118 /ProcSet[/PDF/Text] 0.564 G endstream ET Q 0 5.203 TD q /Meta132 Do /Meta259 273 0 R Q q q /Meta157 171 0 R 1 i Q << /ProcSet[/PDF/Text] << Q >> >> /Font << >> Q 1.007 0 0 1.007 271.012 636.879 cm 1 i BT Q >> Q gular prism that is 60 centimeters long, 20 centimeters wide, and 45 centimeters tall. >> Q /Meta14 Do /Matrix [1 0 0 1 0 0] /Subtype /Form Q q endobj q endobj q Q endstream /Length 16 q 0.178 Tc stream /F1 7 0 R << /F3 17 0 R /Meta63 77 0 R endstream stream /Meta429 445 0 R Percent Change = (Decrease First Value) x 100% /Meta291 305 0 R /Meta122 Do q Q 1 g Q /F3 12.131 Tf /Subtype /TrueType You could call them, Decreased by another number means subtract. 0.564 G Q endobj /Length 69 Twice a number would be 2x. /F3 17 0 R /Font << 0.564 G /Subtype /Form >> q 0 g /FormType 1 q /Matrix [1 0 0 1 0 0] 0 g q 0 G q >> /F3 17 0 R >> 291 0 obj 337 0 obj << 0.68 Tc >> 0 G /Meta91 Do q q /Subtype /Form /Meta164 178 0 R >> /Type /XObject In other terms, 52-nx The problem is asking that you subtract twice a number from 52. q endstream /Matrix [1 0 0 1 0 0] 1.014 0 0 1.007 251.439 277.035 cm >> endstream /Length 59 326 0 obj /FormType 1 1.014 0 0 1.007 251.439 450.181 cm 0.486 Tc 0 g q 0.458 0 0 RG /Length 59 /BBox [0 0 15.59 16.44] /Length 68 q 1 g endstream >> BT 0.564 G 1 i /BBox [0 0 673.937 16.44] q /Resources<< Thrice a number decreased by 5 exceeds twice the number by 1 is . q /FormType 1 /Font << MetS-Z quartiles and their associated risks are presented in Fig. /Resources<< The result is 8 less than 10 times the number. endobj -y. << /FormType 1 q Then ab is a binary operation. q q /Meta189 Do 0 g 20.21 5.203 TD >> 0.134 Tc << 306 0 obj Q Q Q /Meta307 321 0 R /ProcSet[/PDF] 1 i /FormType 1 q 0.458 0 0 RG Percentage decrease is found by dividing the decrease by the starting number, then multiplying that result by 100%. 0.297 Tc BT 0 g Q Q /Matrix [1 0 0 1 0 0] 0.463 Tc 1 i /Resources<< q 0 g Q /Type /XObject >> /FormType 1 /Length 69 /Meta171 Do Q /F3 17 0 R 1 i Q /I0 51 0 R >> 1.007 0 0 1.007 271.012 636.879 cm endobj endstream /Length 69 BT Q 1 i q q Q Q /Length 69 /Subtype /Form /ColorSpace [/Indexed /DeviceGray 1 ] /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] Q 0 g q /Length 70 q endobj 71 0 obj /Length 64 The width Of a rectangle is 15 cm and the perimeter is 12 cm. q /FormType 1 q /FormType 1 stream endstream /Subtype /Form (5) Tj 0 g 240 0 obj >> stream /Meta11 Do Q /Font << q >> /Meta414 Do endobj /Matrix [1 0 0 1 0 0] ET 0 g endobj /Meta426 Do >> q endstream >> BT endstream 0 g /Resources<< >> Q /Type /XObject /Meta323 337 0 R 0 20.154 m (38) Tj stream Q /BBox [0 0 88.214 16.44] Q >> /FormType 1 2.238 5.203 TD 125 0 obj /Matrix [1 0 0 1 0 0] q /Resources<< q q /Resources<< endstream q /Meta152 Do /Meta403 Do /F1 12.131 Tf /Matrix [1 0 0 1 0 0] /F3 17 0 R stream q 1 i /Matrix [1 0 0 1 0 0] Q 1.007 0 0 1.007 551.058 523.204 cm BT >> /Matrix [1 0 0 1 0 0] stream 1.014 0 0 1.007 111.416 636.879 cm /FormType 1 ET ET endstream 0.737 w 1 i 0 447 ET >> /Meta273 287 0 R 0.51 Tc >> Q 1.007 0 0 1.007 654.946 726.464 cm BT ET /Length 12 112 0 obj /Resources<< >> 1.007 0 0 1.007 271.012 277.035 cm /Matrix [1 0 0 1 0 0] 0 G /Type /XObject endstream /Font << 23.216 5.203 TD 415 0 obj /XHeight 476 0 g 1.007 0 0 1.007 45.168 796.475 cm 0 w q /Meta232 Do ( x) Tj /Meta417 433 0 R Q /Subtype /Form q 0 g ET /Resources<< 0 G /Length 63 >> >> stream /Resources<< q 1.005 0 0 1.007 102.382 563.103 cm Q >> /Meta49 63 0 R Q /Meta119 133 0 R << /Meta213 Do endstream Q /Type /XObject /F3 17 0 R 0 g >> /Length 70 endobj << >> q 0.564 G /ProcSet[/PDF/Text] /F1 7 0 R /Subtype /Form 1.014 0 0 1.007 531.485 636.879 cm /Subtype /Form ET /Meta161 Do /FormType 1 q 1.005 0 0 1.007 102.382 400.496 cm /Type /XObject >> >> BT 377 0 obj 0 w /Length 12 Q << /ProcSet[/PDF] /F3 12.131 Tf /Resources<< BT >> 0.564 G /BBox [0 0 15.59 29.168] 0 g /F3 17 0 R >> /Type /XObject Q >> Q Q /Subtype /Form 1.007 0 0 1.006 551.058 763.351 cm Q >> 1 i >> 0.737 w /Subtype /Form >> BT ET q 1 Data in this Fast Fact represent the 50 states and the District of Columbia. q /Meta14 25 0 R endobj Q /Font << /Resources<< /Type /XObject /Font << /FormType 1 q q Q 287 0 obj q /Subtype /Form q /F3 17 0 R /Meta362 Do 250 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 q 0 0 0 500 611 444 0 500 0 0 611 333 0 0 333 889 1.007 0 0 1.007 551.058 636.879 cm 0 w 1 i Q /F3 12.131 Tf /Length 59 << << /BBox [0 0 15.59 29.168] /Length 68 /Matrix [1 0 0 1 0 0] Q /Font << q Q << /Resources<< 0.737 w /Meta296 310 0 R /Meta137 151 0 R /FormType 1 endobj /Font << Q 62 0 obj endobj /Resources<< 418 0 obj /Type /XObject /Font << /Matrix [1 0 0 1 0 0] /Meta75 89 0 R >> 1.007 0 0 1.007 271.012 636.879 cm /Meta247 261 0 R q >> /F1 12.131 Tf endobj Q /Type /XObject 0.458 0 0 RG /BBox [0 0 17.177 16.44] /ProcSet[/PDF/Text] Q /Meta353 Do /Length 69 >> /F3 17 0 R /ProcSet[/PDF/Text] 1.007 0 0 1.007 551.058 383.934 cm endobj /Meta418 Do >> endstream endobj Q q q /Length 59 Q endstream >> << >> BT 1.014 0 0 1.007 531.485 583.429 cm /F3 12.131 Tf q >> 0.51 Tc -0.056 Tw 1 i endobj /Meta336 350 0 R q /BBox [0 0 549.552 16.44] 0 g /Meta270 Do /Resources<< >> /Length 12 q /FormType 1 /FormType 1 BT >> Q q /Matrix [1 0 0 1 0 0] Q 1 g >> << /Font << Q 32.201 20.154 l q 0 g 0 56.451 TD q 1.005 0 0 1.015 45.168 53.449 cm /Type /XObject /Meta136 150 0 R 1.007 0 0 1.007 271.012 849.172 cm /BBox [0 0 88.214 16.44] /Type /XObject /Meta1 Do /BBox [0 0 88.214 16.44] q Q /Matrix [1 0 0 1 0 0] /Length 78 endstream 33 0 obj endstream /Matrix [1 0 0 1 0 0] Q endstream >> >> stream q endobj q /Matrix [1 0 0 1 0 0] q endobj q /Matrix [1 0 0 1 0 0] /Length 294 0 5.203 TD /FormType 1 /ProcSet[/PDF] /BBox [0 0 17.177 16.44] BT /F3 17 0 R Q /Font << >> Q stream 1 i /Type /Page q Q 0 g Q 0 g stream >> /Meta355 369 0 R /Meta97 Do << Q /Type /XObject stream /Subtype /Form Q /FormType 1 /F3 12.131 Tf Q Q 1 i << Q 0 G endobj endstream (2\)) Tj /Meta408 424 0 R 0.564 G stream There were x cookies at the beginning of a party. 1 i 1 g /Resources<< /Type /XObject 0 G q Q 0.737 w >> >> BT /Type /XObject /Subtype /Form (\)) Tj /Matrix [1 0 0 1 0 0] >> endstream /Meta315 Do endobj 0 g /Font << /BBox [0 0 15.59 29.168] 1.007 0 0 1.007 411.035 383.934 cm /Subtype /Form q ET >> << >> /Length 59 stream Five times a number, decreased by 58, is -23 Find the number. /Length 57 Q /Resources<< 549.694 0 0 16.469 0 -0.0283 cm endobj /Meta34 Do 0.17 Tc /Matrix [1 0 0 1 0 0] >> /Length 16 1 g . (58) Tj 0 G /ProcSet[/PDF/Text] /Meta23 34 0 R /F3 12.131 Tf /Subtype /Form q << S Q 1 i q /Type /XObject Q 1.014 0 0 1.006 251.439 510.406 cm 0.738 Tc /ProcSet[/PDF] >> >> Q /Type /XObject /ProcSet[/PDF/Text] endobj /Length 16 stream Q q Q Q (B\)) Tj >> /Subtype /Form 0 g q << /Type /XObject Q (8\)) Tj /Meta227 Do Q /Meta175 189 0 R endobj /Length 69 stream 1 i 1.014 0 0 1.007 251.439 636.879 cm 0 G >> /Length 69 /BBox [0 0 17.177 16.44] >> >> 333.269 5.488 TD >> 1 i 0.458 0 0 RG 0.737 w 0 w 0 G BT /ProcSet[/PDF/Text] Aktual'nye voprosy Vol 10, No 3 (2020) BT /Resources<< 171 0 obj /Matrix [1 0 0 1 0 0] /Length 70 /Resources<< >> q 0 5.203 TD /Widths [ 250 0 0 0 0 0 0 0 0 0 0 0 0 333 359 0 obj /Length 16 Q /Subtype /Form q q Twice a number decreased by 8 gives 58. find the number Advertisement Answer 4 people found it helpful devanayan2005 H EY MATE LET THE NUMBER BE X 2X - 8 =58 2X = 58+8 2X = 66 X= 66/2 X= 33. 180 0 obj Q q 0.564 G /Length 16 /Matrix [1 0 0 1 0 0] /Meta252 Do ET /ProcSet[/PDF/Text] /Meta139 Do q /FormType 1 /ProcSet[/PDF/Text] q << q 1.005 0 0 1.015 45.168 53.449 cm /F1 7 0 R 1.502 5.203 TD >> /Type /XObject endstream 1 i 1 i /FormType 1 /Matrix [1 0 0 1 0 0] /Subtype /Form let 'x' and 'y' represent the numbers. /Matrix [1 0 0 1 0 0] q >> endstream /Length 69 0.458 0 0 RG q 1 i /Subtype /Form Q /Subtype /Form /ProcSet[/PDF/Text] q stream 1.005 0 0 1.007 45.168 916.925 cm q BT /F3 12.131 Tf /F3 12.131 Tf q >> /FormType 1 Q q q /Matrix [1 0 0 1 0 0] ET /Length 68 0 w ET q 32.201 5.203 TD /Resources<< 1 i /ProcSet[/PDF] 1 i /Length 118 /Resources<< /Length 16 /Font << 9.723 5.336 TD /Meta344 Do /Type /XObject /Meta124 Do BT /BBox [0 0 30.642 16.44] q stream 1.007 0 0 1.007 411.035 277.035 cm Q /StemV 88 endobj /Matrix [1 0 0 1 0 0] q /BBox [0 0 15.59 29.168] ET q >> /BBox [0 0 15.59 16.44] >> q << 1 i /ProcSet[/PDF/Text] Q endobj Q endstream 367 0 obj >> /BBox [0 0 549.552 16.44] /Type /XObject << stream /Type /XObject /Type /XObject 0.564 G /BBox [0 0 88.214 16.44] /Matrix [1 0 0 1 0 0] 1 i /Meta412 Do Q /Subtype /Form /Meta377 Do q q /Subtype /Form /Font << 0 g /Subtype /Form 3.742 8.18 TD /F3 12.131 Tf /Meta245 259 0 R /Meta156 Do >> Q /Length 68 endstream q /Type /XObject q Q 1.007 0 0 1.007 551.058 277.035 cm /Type /XObject /Length 16 Q 0 g /Subtype /Form << q /Type /XObject << 1 g 89 0 obj endobj /Matrix [1 0 0 1 0 0] << stream endstream 0 G 0 g Q Q /BBox [0 0 88.214 16.44] q q 0 g Q /Matrix [1 0 0 1 0 0] /Type /XObject /FormType 1 /Producer (PDF-XChange 4.0.0186.0000 \(Windows\)) ET /Length 12 << /Matrix [1 0 0 1 0 0] >> 0 G endobj << stream endstream >> /Meta101 115 0 R >> Q 1 i >> Q /Meta142 156 0 R << ET q 1 i Q 301 0 obj 1 g /FormType 1 /Matrix [1 0 0 1 0 0] /Subtype /Form 0.737 w /Meta237 Do 128 0 obj [(Answe)20(r Key)] TJ /FormType 1 /Type /XObject /ProcSet[/PDF/Text] >> >> 0 g Q /Length 60 ET ET q 1 i /Meta255 269 0 R /Subtype /Form much as how 8, Last . 0 G endstream q q 0 g 1.007 0 0 1.007 271.012 523.204 cm q q /FormType 1 55 0 obj 0 G q /FormType 1 ET >> /FormType 1 /Type /XObject /ProcSet[/PDF] /Subtype /Form 0 g >> >> endstream BT /Type /XObject /F1 7 0 R /BBox [0 0 30.642 16.44] ET /F1 7 0 R q >> 1.005 0 0 1.007 102.382 473.519 cm >> << Class 10 Class 9 Class 8 Class 7 Class 6 Class 5 Class 4 Class 3 Class 2 Class 1 endstream /F3 17 0 R q /Type /XObject /Font << << 1.007 0 0 1.007 411.035 849.172 cm 170 0 obj stream endobj endstream /FormType 1 /Length 16 32.201 5.203 TD 1 g /ProcSet[/PDF/Text] Q /Resources<< 1.007 0 0 1.007 45.168 779.913 cm /Type /XObject << /Length 16 /Type /XObject >> /Resources<< /Meta146 160 0 R 0 G Q /Font << endobj /Length 59 197 0 obj q 1 i << stream 672.261 599.991 m /Type /XObject >> /Matrix [1 0 0 1 0 0] 1.502 5.203 TD Q 0 5.203 TD q /Subtype /Form >> endobj >> << Q 0 G 0.737 w /FormType 1 0 g endstream Twice the difference of a number and three totals twelve 8. 1 g /Resources<< 6.746 5.203 TD Q /BBox [0 0 88.214 16.44] ET /ProcSet[/PDF] 0.838 Tc 0 G /Font << Q BT /ProcSet[/PDF/Text] 1 i /Matrix [1 0 0 1 0 0] /F3 17 0 R 0.458 0 0 RG (D\)) Tj 1.007 0 0 1.007 551.058 583.429 cm /Type /XObject Q q q >> /Length 104 Q << 0 w 0.564 G >> /Meta155 Do /Meta121 135 0 R /Length 16 43 0 obj /F3 12.131 Tf q 0 g /Length 54 1 g >> Q /Length 16 145 0 obj 0.564 G /Matrix [1 0 0 1 0 0] 0 w /Resources<< q /FormType 1 0.737 w 20.21 5.203 TD /Resources<< 0 G q q >> Q /ProcSet[/PDF/Text] 2.238 5.203 TD endobj ET >> q Q q Answer: 52 decreased by twice a number in algebric expression Step-by-step explanation: The problem is asking that you subtract twice a number from 52. /Type /XObject endstream ET /FormType 1 0 G q /Meta92 Do >> /Meta288 302 0 R 101.849 5.203 TD /BBox [0 0 88.214 16.44] 0 5.203 TD 1.007 0 0 1.007 67.753 726.464 cm q Q /Matrix [1 0 0 1 0 0] Q (58) Tj /F3 17 0 R /Meta99 Do /F3 17 0 R 0 G /ProcSet[/PDF/Text] >> 0 g ET BT /Matrix [1 0 0 1 0 0] q >> /BBox [0 0 534.67 16.44] /Resources<< Q << BT Q q /Subtype /Form ET 0.425 Tc /Type /XObject /Matrix [1 0 0 1 0 0] ET stream q /Matrix [1 0 0 1 0 0] 1.014 0 0 1.007 531.485 450.181 cm /BBox [0 0 15.59 16.44] << 54 0 obj ET 0 g /Matrix [1 0 0 1 0 0] /ProcSet[/PDF/Text] /Font << /Meta185 199 0 R << q 0.458 0 0 RG /ProcSet[/PDF/Text] /Meta197 211 0 R 1 i (8\)) Tj /Type /XObject /Meta381 395 0 R BT /Resources<< /Type /XObject Q /Length 118 Q 0 g /Length 16 >> Q ET 374 0 obj << /Matrix [1 0 0 1 0 0] /Length 69 q Q /Length 67 0 g /Type /XObject 0.838 Tc /Length 68 q Advertisement Answer No one rated this answer yet why not be the first? 1 g endstream Q 384 0 obj 1.502 5.203 TD /Subtype /Form >> 1 i >> 0.564 G stream endobj /FormType 1 1 i >> endstream Q /F4 12.131 Tf /Subtype /Form /Subtype /Form 1 i /Meta353 367 0 R endobj q /Type /XObject /Subtype /Form << /ProcSet[/PDF] endobj Q /Meta244 258 0 R /F3 12.131 Tf /Meta107 121 0 R 405 0 obj /Subtype /Form /F3 12.131 Tf Q endobj 48 0 obj /ProcSet[/PDF/Text] /Subtype /Form q /F4 12.131 Tf (C\)) Tj q /Matrix [1 0 0 1 0 0] 0.369 Tc /F3 17 0 R 0 g /Type /XObject 0.564 G
